["python","generator"]
Get the nth item of a generator in Python

Is there a more syntactically concise way of writing the following? gen = (i for i in xrange(10)) index = 5 for i, v in enumerate(gen): if i is index: return v It seems almost natural that a generator should have a gen[index] expression, that acts as a list, but is functionally identical to the above code.
one method would be to use itertools.islice >>> gen = (x for x in range(10)) >>> index = 5 >>> next(itertools.islice(gen, index, None)) 5