["python","list","tuples","list-comprehension"]
How to unzip a list of tuples into individual lists?

I have a list of tuples l = [(1,2), (3,4), (8,9)]. How can I, succinctly and Pythonically, unzip this list into two independent lists, to get [ [1, 3, 8], [2, 4, 9] ]? In other words, how do I get the inverse of what zip does?
Use zip(*list): >>> l = [(1,2), (3,4), (8,9)] >>> list(zip(*l)) [(1, 3, 8), (2, 4, 9)] The zip() function pairs up the elements from all inputs, starting with the first values, then the second, etc. By using *l you apply all tuples in l as separate arguments to the zip() function, so zip() pairs up 1 with 3 with 8 first, then 2 with 4 and 9. Those happen to correspond nicely with the columns, or the transposition of l. zip() produces tuples; if you must have mutable list objects, just map() the tuples to lists or use a list comprehension to produce a list of lists: map(list, zip(*l)) # keep it a generator [list(t) for t in zip(*l)] # consume the zip generator into a list of lists