["python","math","python-2.x","sqrt"]
Why does Python give the "wrong" answer for square root? What is integer division in Python 2?

x = 16 sqrt = x**(.5) #returns 4 sqrt = x**(1/2) #returns 1 I know I can import math and use sqrt, but I'm looking for an answer to the above. What is integer division in Python 2? This behavior is fixed in Python 3.
In Python 2, sqrt=x**(1/2) does integer division. 1/2 == 0. So x(1/2) equals x(0), which is 1. It's not wrong, it's the right answer to a different question. If you want to calculate the square root without an import of the math module, you'll need to use x**(1.0/2) or x**(1/2.). One of the integers needs to be a floating number. Note: this is not the case in Python 3, where 1/2 would be 0.5 and 1//2 would instead be integer division.