["python","time","python-3.x"]
How to delete last item in list?

I have this program that calculates the time taken to answer a specific question, and quits out of the while loop when answer is incorrect, but i want to delete the last calculation, so i can call min() and it not be the wrong time, sorry if this is confusing. from time import time q = input('What do you want to type? ') a = ' ' record = [] while a != '': start = time() a = input('Type: ') end = time() v = end-start record.append(v) if a == q: print('Time taken to type name: {:.2f}'.format(v)) else: break for i in record: print('{:.2f} seconds.'.format(i))
If I understood the question correctly, you can use the slicing notation to keep everything except the last item: record = record[:-1] But a better way is to delete the item directly: del record[-1] Note 1: Note that using record = record[:-1] does not really remove the last element, but assign the sublist to record. This makes a difference if you run it inside a function and record is a parameter. With record = record[:-1] the original list (outside the function) is unchanged, with del record[-1] or record.pop() the list is changed. (as stated by @pltrdy in the comments) Note 2: The code could use some Python idioms. I highly recommend reading this: Code Like a Pythonista: Idiomatic Python (via wayback machine archive).