["python","urllib","urlparse"]
How to extract a filename from a URL and append a word to it?

I have the following URL: url = http://photographs.500px.com/kyle/09-09-201315-47-571378756077.jpg I would like to extract the file name in this URL: 09-09-201315-47-571378756077.jpg Once I get this file name, I'm going to save it with this name to the Desktop. filename = **extracted file name from the url** download_photo = urllib.urlretrieve(url, "/home/ubuntu/Desktop/%s.jpg" % (filename)) After this, I'm going to resize the photo, once that is done, I've going to save the resized version and append the word "_small" to the end of the filename. downloadedphoto = Image.open("/home/ubuntu/Desktop/%s.jpg" % (filename)) resize_downloadedphoto = downloadedphoto.resize.((300, 300), Image.ANTIALIAS) resize_downloadedphoto.save("/home/ubuntu/Desktop/%s.jpg" % (filename + _small)) From this, what I am trying to achieve is to get two files, the original photo with the original name, then the resized photo with the modified name. Like so: 09-09-201315-47-571378756077.jpg rename to: 09-09-201315-47-571378756077_small.jpg How can I go about doing this?
You can use urllib.parse.urlparse with os.path.basename: import os from urllib.parse import urlparse url = "http://photographs.500px.com/kyle/09-09-201315-47-571378756077.jpg" a = urlparse(url) print(a.path) # Output: /kyle/09-09-201315-47-571378756077.jpg print(os.path.basename(a.path)) # Output: 09-09-201315-47-571378756077.jpg Your URL might contain percent-encoded characters like %20 for space or %E7%89%B9%E8%89%B2 for "特色". If that's the case, you'll need to unquote (or unquote_plus) them. You can also use pathlib.Path().name instead of os.path.basename, which could help to add a suffix in the name (like asked in the original question): from pathlib import Path, PurePosixPath from urllib.parse import urlparse, unquote url = "http://photographs.500px.com/kyle/09-09-2013%20-%2015-47-571378756077.jpg" urlparse(url).path url_parsed = urlparse(url) print(unquote(url_parsed.path)) # Output: /kyle/09-09-2013 - 15-47-571378756077.jpg file_path = Path("/home/ubuntu/Desktop/") / unquote(PurePosixPath(url_parsed.path).name) print(file_path) # Output: /home/ubuntu/Desktop/09-09-2013 - 15-47-571378756077.jpg new_file = file_path.with_stem(file_path.stem + "_small") print(new_file) # Output: /home/ubuntu/Desktop/09-09-2013 - 15-47-571378756077_small.jpg For parsing URL paths, note that pathlib.PurePosixPath is more specific and more applicable than pathlib.Path. Also, a less-robust alternative is to use unquote(urlparse(url).path.split("/")[-1]).