["python","list"]
Remove all occurrences of a value from a list?

In Python remove() will remove the first occurrence of value in a list. How to remove all occurrences of a value from a list? This is what I have in mind: >>> remove_values_from_list([1, 2, 3, 4, 2, 2, 3], 2) [1, 3, 4, 3]
Functional approach: Python 3.x >>> x = [1,2,3,2,2,2,3,4] >>> list(filter((2).__ne__, x)) [1, 3, 3, 4] or >>> x = [1,2,3,2,2,2,3,4] >>> list(filter(lambda a: a != 2, x)) [1, 3, 3, 4] or >>> [i for i in x if i != 2] Python 2.x >>> x = [1,2,3,2,2,2,3,4] >>> filter(lambda a: a != 2, x) [1, 3, 3, 4]