["python","dictionary","map-function"]
Mapping over values in a python dictionary

Given a dictionary { k1: v1, k2: v2 ... } I want to get { k1: f(v1), k2: f(v2) ... } provided I pass a function f. Is there any such built in function? Or do I have to do dict([(k, f(v)) for (k, v) in my_dictionary.iteritems()]) Ideally I would just write my_dictionary.map_values(f) or my_dictionary.mutate_values_with(f) That is, it doesn't matter to me if the original dictionary is mutated or a copy is created.
There is no such function; the easiest way to do this is to use a dict comprehension: my_dictionary = {k: f(v) for k, v in my_dictionary.items()} Note that there is no such method on lists either; you'd have to use a list comprehension or the map() function. As such, you could use the map() function for processing your dict as well: my_dictionary = dict(map(lambda kv: (kv[0], f(kv[1])), my_dictionary.items())) but that's not that readable, really. (Note that if you're still using Python 2.7, you should use the .iteritems() method instead of .items() to save memory. Also, the dict comprehension syntax wasn't introduced until Python 2.7.)