["python","timer"]
How to repeatedly execute a function every x seconds?

I want to repeatedly execute a function in Python every 60 seconds forever (just like an NSTimer in Objective C or setTimeout in JS). This code will run as a daemon and is effectively like calling the python script every minute using a cron, but without requiring that to be set up by the user. In this question about a cron implemented in Python, the solution appears to effectively just sleep() for x seconds. I don't need such advanced functionality so perhaps something like this would work while True: # Code executed here time.sleep(60) Are there any foreseeable problems with this code?
If your program doesn't have a event loop already, use the sched module, which implements a general purpose event scheduler. import sched, time def do_something(scheduler): # schedule the next call first scheduler.enter(60, 1, do_something, (scheduler,)) print("Doing stuff...") # then do your stuff my_scheduler = sched.scheduler(time.time, time.sleep) my_scheduler.enter(60, 1, do_something, (my_scheduler,)) my_scheduler.run() If you're already using an event loop library like asyncio, trio, tkinter, PyQt5, gobject, kivy, and many others - just schedule the task using your existing event loop library's methods, instead.