["python","flask"]
Flask doesn't print to console

I'm new to flask, and I'm trying to add print info to debug server side code. When launch my flask app with debug=True, i can't get any info print to console I tried to use logging instead, but no success. So how to debug flask program with console. @app.route('/getJSONResult', methods=['GET', 'POST']) def getJSONResult(): if request.method == 'POST': uut = request.form['uut'] notes = request.form['notes'] temperature = request.form['temperature'] logging.info("enter getJSONReuslt") print('enter getJSONReuslt') filter_by_query = {k: v for k, v in { 'uut': uut, 'notes': notes, 'temperature': temperature}.items() if v != ""} s = session.query(UUT_TEST_INFO).filter_by(**filter_by_query).first() return jsonify(s.serialize) if __name__ == '__main__': app.secret_key = ''.join(random.choice( string.ascii_uppercase + string.digits) for x in range(32)) app.debug = True app.run(host='127.0.0.1', port=5000) > 127.0.0.1 - - [07/Jun/2017 15:20:48] "GET /qyer HTTP/1.1" 200 - > 127.0.0.1 - - [07/Jun/2017 15:20:48] "GET /static/css/bootstrap.min.css HTTP/1.1" 200 - > 127.0.0.1 - - [07/Jun/2017 15:20:48] "GET /static/js/bootstrap.min.js HTTP/1.1" 200 - > 127.0.0.1 - - [07/Jun/2017 15:20:51] "GET /static/css/bootstrap.min.css.map HTTP/1.1" 200 - > 127.0.0.1 - - [07/Jun/2017 15:21:58] "POST /getJSONResult HTTP/1.1" 500 - I fixed server side 500 error issue, now request get 200 code, and console displays following info $ python project.py INFO:werkzeug: * Running on http://127.0.0.1:5000/ (Press CTRL+C to quit) INFO:werkzeug: * Restarting with stat WARNING:werkzeug: * Debugger is active! INFO:werkzeug: * Debugger pin code: 158-624-607 INFO:werkzeug:127.0.0.1 - - [08/Jun/2017 11:33:33] "GET /qyer HTTP/1.1" 200 - INFO:root:Enter getJSONResult INFO:werkzeug:127.0.0.1 - - [08/Jun/2017 11:33:43] "POST /getJSONResult HTTP/1.1" 200 - Still no info from print command
Try this and see if it helps: For python2: from __future__ import print_function import sys print('This is error output', file=sys.stderr) print('This is standard output', file=sys.stdout) For python3 you don't need to import from future print_function: import sys print('This is error output', file=sys.stderr) print('This is standard output', file=sys.stdout) See if it helps to print to console.